The exponential Diophantine equation (3am2−1)x+(a(a−3)m2+1)y=(am)z(3am2−1)x+(a(a−3)m2+1)y=(am)z(3am^2-1)^x+(a(a-3)m^2+1)^y=(am)^z

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Turkish Journal of Mathematics 2019 Vol.43 Issue 5, pp.2561-2567

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